Work-Energy Theorem

Statement: The net work done on a body is equal to the change in kinetic energy of that body.

$\text{Work done (W) = Force (F) . Displacement (s)}$

And

$\text{Force (F) = mass (m) . acceleration (a)}$

So

$\text{W = mas}$

We know,

$\text{v}^2 \text{ = u}^2 \text{ + 2as}$

$\implies \text{as} = \dfrac{\text{v}^2 – \text{u}^2}{2}$

Put

$\text{W = m . }\dfrac{\text{v}^2 – \text{u}^2}{2}$

$\text{W = } \dfrac{1}{2} \text{mv}^2 \text{ – }\dfrac{1}{2}\text{mu}^2$

$\text{W = KE}_{\text{final}} \text{- KE}_{\text{initial}}$

$\text{Work Done = Change in Kinetic Energy}$